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The side of a cube is (2.00 pm 0.01) cm....

The side of a cube is `(2.00 pm 0.01)` cm. The volume and surface area of cube are respectively :-

A

`(8.00 pm 0.12) cm^(3),(24.0 pm 0.24) cm^(2)`

B

`(8.00 pm 0.01)cm^(3),(24.0 pm 0.01)cm^(2)`

C

`(8.00 pm 0.04)cm^(3),(24.0 pm 0.06)cm^(2)`

D

`(8.00 pm 0.03)cm^(3),(24.0 pm 0.02)cm^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A

Volume `V=a^(3)=8cm^(3)` Also `(Delta V)/(V)=3(Delta a)/(a)rArr Delta V=3V((Delta a)/(a))=(3)(8)((0.01)/(2.00))=0.12 cm^(3)`
Therefore `V=(8.00 pm 0.12)cm^(3)`, Surface Area `A=6a^(2)=6(2.00)^(2)=24.0 cm^(2)`
Also `(A A)/(A)=2(Delta a)/(a)rArr DeltaA=2A((Delta a)/(a))=2(24.0)((0.01)/(2.00))=0.24` Therefore `A=(24.0 pm 0.24)cm^(2)`.
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