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A train is moving along a straight line ...

A train is moving along a straight line with a constant acceleration 'a' . A boy standing in the train throws a ball forward with a speed of `10 m//s `, at an angle of `60(@)` to the horizontal. The boy has to move forward by `1.15 m ` inside the train to catch the ball back at the initial height . the acceleration of the train , in `m//s^(2)` , is

Text Solution

Verified by Experts

The correct Answer is:
5
With respect to train:
Time of flight : `T=(2v_(y))/g=(2xx5sqrt(3))/10=sqrt(3)`
By using `s=ut+1/2 at^(2)`
we have `1.15=5T-1/2 aT^(@)rArr a=5 m//s^(2)`
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Knowledge Check

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