Find the equation of the tangent to the curve `y=sqrt(3x-2)` which is parallel to the line `4x-2y+5=0`

Explanation

Slope of the given line is 2

Let `(x_{1}, y_{1})` be the point where the tangent is drawn to the curvey `=sqrt{3 x-2}`

Since, the point lies on the curve.

Hence,`y_{1}=sqrt{3 x_{1}-2} ldots` (1)

Now,`y=sqrt{3 x-2}`

`Rightarrow frac{d y}{d x}=frac{3}{2 sqrt{3 x-2}}`

Slope of tangent at `(x_{1}, y_{1})=frac{3}{2 sqrt{3 x_{1}-2}}`

Given that

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