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The specific conducitvity of a saturated...

The specific conducitvity of a saturated solution of `AgCI` is ` 3.40 xx 10^6 "ohm"^(-1) cm^(-1) ` at ` 25^@C`. If ` lambda_(Ag+) = 62.3 "ohm"^(-1) cm^2 "mol"^(-1)` and `lambda_(CI-) = 67.7 "ohm"^(-1) cm^2 "mol"^(-1)`, the solubility of `AgCI` at `25^@C` is.

A

`2.6xx10^(-5) "mol" L^(-1)`

B

`3.731xx10^(-3) "mol" L^(-1)`

C

`3.731xx10^(-5) "mol" L^(-1)`

D

`2.6xx10^(-3)g L^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`lambda_(AgCl)=)62.3+67.7)Omega^(-) "mol"^(-1)`
`=130 Omega^(-)"mol"^(-1)`
`s=(kxx1000)/(lambda_(AgCl))=(3.4xx10^(-6)xx1000)/(130)=2.6xx10^(-5) "mol" L^(-1)`
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Knowledge Check

  • The specific conductivity of a saturated solution of AgCl is 3.40xx10^(-6) ohm^(-1) cm^(-1) at 25^(@)C . If lambda_(Ag^(+)=62.3 ohm^(-1) cm^(2) "mol"^(-1) and lambda_(Cl^(-))=67.7 ohm^(-1) cm^(2) "mol"^(-1) , the solubility of AgC at 25^(@)C is:

    A
    `2.6xx10^(-5)M`
    B
    `4.5xx10^(-3)M`
    C
    `3.6xx10^(-5)M`
    D
    `3.6xx10^(-3)M`

  • The specific conductivity of a standard solution of AgCl is 1.40 xx 10^(-6) "ohm"^(-1) cm^(-1) at 25^(@)C . If lambda_(Ag^(+))^(@) = 62.3 "ohm"^(-1) cm^(2) mol^(-1) & lambda_(Cl^(-1)) = 67.7 "ohm"^(-1) cm^(2) "mol"^(-1) , the solubility of AgCl at 25^(@) C is:

    A
    `2.6 xx 10^(-5) M`
    B
    `4.5 xx 10^(-3) M`
    C
    `3.6 xx 10^(-5) M`
    D
    `3.6 xx 10^(-1) M`

  • The specific conductivity of a standard solution of AgCl is 1.40 xx 10^(-6) "ohm"^(-1) cm^(-1) at 25^(@)C . If lambda_(Ag^(+))^(@) = 62.3 "ohm"^(-1) cm^(2) mol^(-1) & lambda_(Cl^(-1)) = 67.7 "ohm"^(-1) cm^(2) "mol"^(-1) , the solubility of AgCl at 25^(@) C is:

    A
    `2.6 xx 10^(-5) M`
    B
    `4.5 xx 10^(-3) M`
    C
    `3.6 xx 10^(-5) M`
    D
    `3.6 xx 10^(-1) M`

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