Home
Class 12
CHEMISTRY
Ch(2)=C=Ch-CH(3), total numbe rof sigma ...

`Ch_(2)=C=Ch-CH_(3),` total numbe rof `sigma` & `pi` bonds in given compound will be :-

A

`3,3`

B

`9,2`

C

`2,9`

D

`1,2`

Text Solution

Verified by Experts

The correct Answer is:
B
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

CH_(3)-CH_(2)-CO-CH=CH-C-=CH The ratio of sigma and pi bonds present in above compound is K . Then 10K is

CH_3-CH_2-CO-CH=CH-C-=CH . The ratio of sigma and pi bonds present in the above compound is K. Then 10 K is ___

Knowledge Check

  • Number of bonds in given compound is: CH_(2)=C=CH-C=CH

    A
    10
    B
    12
    C
    14
    D
    16

  • Me (CH=CH-CH=C=CH-CH=CH_(2) Total number of geometrical isomers possible for above compound are:

    A
    16
    B
    8
    C
    4
    D
    2

  • How many pi and sigma bonds are in the given compound? HC-=C-CH=CH_(2)

    A
    `3pi` and `6sigma` bonds
    B
    `3pi` and `7sigma` bonds
    C
    `2pi` and `7sigma` bonds
    D
    `4pi` and `8sigma` bonds

    • Similar Questions

    Explore conceptually related problems

    Total number of sigma bonds in the compound CH_(3)-CH_(2)-CO-CN are 2"x" .Then the value of "x" is

    CH_(3)CHO+NH_(2)OH toY . The number of sigma bonds, pi bonds and lone pairs of electrons in the compound 'Y' are respectively

    The number of sigma bonds present in the CH_2 =CH_2 molecule is

    The number of sigma bonds present in the CH_2 = C = CH_2 is

    The number of sigma bonds present in the CH_2 = C= CH-CH_3 molecule is

    Home
    Profile