A sodium street light gives off yellow light that has a wavelength of `600 n m.` Then .

Options

A. frequency of this light is `7xx10^(14)s^(-1)`
B. frequency of this light is `5xx10^(14)s^(-1)`
C. wavenumber of the light is `3xx10^(8)m^(-1)`
D. energy of the photon is approximately `4.14 eV`

Answer

2

Explanation

`V=(C)/(lambda)=(3xx10^(8))/(6000xx10^(-10))=5xx10^(14)S^(-1)`. Energy of photon `=(12400)/(6000)=2.07eV`