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A sodium street light gives off yellow l...

A sodium street light gives off yellow light that has a wavelength of `600 n m.` Then .

A

frequency of this light is `7xx10^(14)s^(-1)`

B

frequency of this light is `5xx10^(14)s^(-1)`

C

wavenumber of the light is `3xx10^(8)m^(-1)`

D

energy of the photon is approximately `4.14 eV`

Text Solution

Verified by Experts

The correct Answer is:
2
`V=(C)/(lambda)=(3xx10^(8))/(6000xx10^(-10))=5xx10^(14)S^(-1)`. Energy of photon `=(12400)/(6000)=2.07eV`
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Knowledge Check

  • A sodium street light gives off yellow light that has a wavelength of 600 nm. Then (For energy of a photon take E=(12400eV-"Å")/(lambda("Å")):

    A
    frequency of this light is `7xx10^(14)s^(-1)`
    B
    frequency of this light is `5xx10^(14)s^(-1)`
    C
    wave number of the light is `3xx10^(6) m^(-1)`
    D
    energy of the photon is approximately 2.07 eV

  • The frequency of yellow light having wavelength 600 nm is

    A
    `5.0xx10^14` Hz
    B
    `2.5xx10^7` Hz
    C
    `5.0xx10^7` Hz
    D
    `2.5xx10^14` Hz

  • A modern 200 W sodium street lamp emits yellow light of wavelength 0.6 mum . Assuming it to be 25% efficient in converting electrical energy to light, the number of photons of tellow light it emits per second is

    A
    `62xx10^(20)`
    B
    `3xx10^(19)`
    C
    `1.5xx10^(20)`
    D
    `6xx10^(18)`

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