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A long taut string is plucked at its ce...

A long taut string is plucked at its centre. The pulse travelling on it can be described as `y (x, t) = e^(-(x+2t)^(2))+e^(-(x-2t)^(2))`. Draw the shape of the string at time `t=0`, a short time after `t=0` and a long time after `t=0`.

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The correct Answer is:
`(##IJA_PHY_V01_C13_E01_041_A01##)`
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Knowledge Check

  • If S=2t^(3)-4t^(2)+12t , then distance travelled during the time -interval [0,1] is

    A
    4 units
    B
    9 units
    C
    8 units
    D
    10 units

  • A string of length 0.4 m and mass 10^(-2) kg is clamped at its ends. The tension in the string is 1.6 N. When a pulse travels along the string the shape of the string is found to be the same at times t and t+trianglet . The value trianglet is

    A
    0.05s
    B
    0.1s
    C
    0.2s
    D
    0.4s

  • If at t = 0 , a travelling wave pulse on a string is described by the function. y = (6)/(x^(2) + 3) What will be the waves function representing the pulse at time t , if the pulse is propagating along positive x-axis with speed 4m//s ?

    A
    `y=(6)/(x+4t)^(2) +3`
    B
    `y=(6)/(x - 4t)^(2) +3`
    C
    `y =(6)/(x - t)^(2)`
    D
    `y =(6)/(x - t)^(2)+12`

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