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The solubility of Ba(OH)(2). 8H(2)O in w...

The solubility of `Ba(OH)_(2)`. `8H_(2)O` in water at `288K` is `5.6g` per `100g` of water. What is the molality hydroxide ions in saturated solution of `Ba(OH)_(2)`. `8H_(2)O` at `288K` ? [At. Mass of `Ba=137,O=16,H=1`)

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Verified by Experts

The correct Answer is:
`0.356m`
`2xx` moles of `Ba(OH)_(2)=` moles of `OH^(-)`
`2xx(5.6)/(315)=` moles of `OH^(-)`
molality of `OH=2xx(5.6)/(315)xx(1000)/(100)=0.356m`.
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Knowledge Check

  • The number of moles of hydroxide (OH^(-)) ion in 0.3 litre of 0.005 M solution of Ba(OH)_(2) is

    A
    0.005
    B
    0.003
    C
    0.0015
    D
    0.0075

  • The O.N of P in Ba(H_(2)PO_(2))_(2) is:

    A
    `+3`
    B
    `+2`
    C
    `+1`
    D
    `-1`

  • Ph of a saturated solution of Ba(OH)_(2) " is " 12 . The value of solubility product is :

    A
    `3.3 xx 10^(-7)`
    B
    `5.0 xx 10^(-7)`
    C
    `4.0 xx 10^(-6)`
    D
    `5.0 xx 10^(-6)`
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