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6.02xx10^(20) molecules of urea are pres...

`6.02xx10^(20)` molecules of urea are present in `100 mL` solution. The concentration of urea solution is:

A

`0.001M`

B

`0.001M`

C

`0.02M`

D

`0.1M`.

Text Solution

Verified by Experts

The correct Answer is:
B
Moles of urea `=(6.02xx10^(20))/(6.02xx10^(23))=10^(-3)` moles
concentration (molarity) of solution `=(10^(-3))/(100)xx1000=0.01M`.
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