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6.02xx10^(20) molecules of urea are pres...

`6.02xx10^(20)` molecules of urea are present in `100 mL` solution. The concentration of urea solution is:

A

`0.001M`

B

`0.001M`

C

`0.02M`

D

`0.1M`.

Text Solution

Verified by Experts

The correct Answer is:
B
Moles of urea `=(6.02xx10^(20))/(6.02xx10^(23))=10^(-3)` moles
concentration (molarity) of solution `=(10^(-3))/(100)xx1000=0.01M`.
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Knowledge Check

  • 6.0xx10^(20) molecules of urea are present in 100 L of his solution. The concentration of urea solution is

    A
    0.001 M
    B
    0.1 M
    C
    0.02 M
    D
    0.01 M

  • 6.02 xx 10^(20) molecules of urea are present in 100 mL of its solution. The concentration of urea solution is (Avogadro constant, N_(A) = 6.02 xx 10^(23)mol^(-1))

    A
    `0.001 M`
    B
    `0.1M`
    C
    `0.002M`
    D
    `0.01`

  • 6.02xx10^(20) molecules of urea are present in 100 mL of its solution. The concentration of the solution is

    A
    0.02 M
    B
    0.01 M
    C
    0.001 M
    D
    0.1 M