Many a time the reaction are carried out...

Many a time the reaction are carried out when the reactants are not present in the amounts required by a balanced chemical reaction. In such situations, one reactant is in excess over other. The reactant which is present in th lesser amount gets conserved after sometime and after that no further reaction takes place whatever be the amount of other reactant is present .Hence, the reactant which gets consumed , limits the amount of products formed and is therefore called limiting reagent.
To determine the limiting reagent find the value of `phi` which is the ratio of (given) mole of a substance to the stoichiometric coefficient of that substance . The limiting reagent is the reagent which has minimum value of `phi`.
In the above question , how much reactant is remaining at the completion of reaction and which one?

Nothing

5.9 kg `Cr_(2)O_(3)`

14.1 kg `Cr_(2)O_(3)`

14.1 kg Al

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Many a time the reaction are carried out when the reactants are not present in the amounts required by a balanced chemical reaction. In such situations, one reactant is in excess over other. The reactant which is present in th lesser amount gets conserved after sometime and after that no further reaction takes place whatever be the amount of other reactant is present .Hence, the reactant which gets consumed , limits the amount of products formed and is therefore called limiting reagent. To determine the limiting reagent find the value of phi which is the ratio of (given) mole of a substance to the stoichiometric coefficient of that substance . The limiting reagent is the reagent which has minimum value of phi . The reduction of Cr_(2)O+_(3) by Al proceeds quantitatively on ignition of a suitable fuse. The reaction is : 2Al +Cr_(2)O_(3) rarr Al_(2)O_(3) +2Cr How much metallic chromium can be made by bringing to reaction temperature a mixture of 5 kg Al and 20 kg Cr_(2)O_(3) ?

9.6 kg

14.4 kg

5.9 kg

1.41 kg

157 lb

71.3 lb

84 lb

15 lb

`MeCOOEt` and `(EtO-underset(O)underset(||)(C)-underset(O)underset(||)(C)-Et)`

`EtCOOEt + EtOOC - COOEt`

`(EtOOC-underset(Me)underset(|)(CH)-COOEt+HCOOEt)`

`EtCOOEt + HCOOEt`.