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The wavelenght of a certain line in the ...

The wavelenght of a certain line in the Paschen series in 1093.6 nm What is the value of higher orbital for lt brgt this line .`[R=10.973xx10^(+7)m^(-1)]`.

Text Solution

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The correct Answer is:
6
`(1)/(lambda)=R[(1)/(n^(2))-(1)/(n_(2)^(2)]]`
`(1)/(1.093xx10^(-6))=R[(1)/(3^(2))-(1)/(n_(2)^(2)]]`
`n_(2)^(2)=36`
`n_(2)=6`
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The wavelength of a certain line in the Pashchen series is 1093.6nm . What is the value of n_(high) for this line [R_(H)=1.0973xx10^(-7)m^(-1)]

Calculate longest wavelength of Paschen series. Given R=1.097xx10^(7)m^(-1) .

Knowledge Check

  • Wavelength of the first line of Paschen series is - (R = 109700 cm^-1 )

    A
    `[18750 Å]`
    B
    `[2854 Å]`
    C
    `[3452 Å]`
    D
    `[6243 Å]`

  • The wavelength of the K_a line for the uranium is (Z = 92) (R = 1.0973xx10^7m^(-1)

    A
    `1.5 Å`
    B
    `0.5 Å`
    C
    `0.15 Å`
    D
    `2.0 Å`

  • The velocity of an e in excited state of H-atom is 1.093 xx 10^(6)m//s , what is the circumference of this orbit?

    A
    `3.32 xx 10^(-10)m`
    B
    `6.64 xx 10^(-10)m`
    C
    `13.30 xx 10^(-10)m`
    D
    `13.28 xx 10^(-8)m`

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