Home
Class 11
PHYSICS
A gas expands with temperature according...

A gas expands with temperature according to the relation `V = kT^(2//3)`. What is the work done when the temperature changes by `30^(@)C`?

A

`10R`

B

`20R`

C

`30R`

D

`40R`

Text Solution

Verified by Experts

The correct Answer is:
B
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • THERMODYNAMICS

    CENGAGE PHYSICS|Exercise 9|3 Videos

  • THERMODYNAMICS

    CENGAGE PHYSICS|Exercise 10|3 Videos

  • THERMODYNAMICS

    CENGAGE PHYSICS|Exercise 7|3 Videos

  • SUPERPOSITION AND STANDING WAVES

    CENGAGE PHYSICS|Exercise Comprehension Type|5 Videos

  • TRANSMISSION OF HEAT

    CENGAGE PHYSICS|Exercise Single correct|9 Videos

Similar Questions

Explore conceptually related problems

The volume V of a given mass of monoatomic gas changes with temperature T according to the relation V=KT^(2//3) . The workdone when temperature changes by 90 K will be xR. The value of x is [R = universal gas constant]

One mole of an ideal gas at a temperature T_(1) expands according to the law (p)/(V)= a constant.Findthe work donw when the final temperature is T_(2)

Knowledge Check

  • A gas expands with temperature according to the relation V=KT^(2/3) .Work done when the temperature changes by 60K is.

    A
    10R
    B
    30R
    C
    40R
    D
    20R

  • A gas expands with temperature according to the relation V = KT^(2//3) where K is a constant. The work done by the gas when the temperature changes by 60 K is

    A
    10 R
    B
    30 R
    C
    40 R
    D
    20 R

  • One mole of an ideal gas at temperature T_(1) expands according to the law (P/V) = constant. Find the work done when the final temperature becomes T_(2) .

    A
    `R(T_(2) - T_(1))`
    B
    `(R//2)(T_(2) - T_(1))`
    C
    `(R//4)(T_(2) - T_(1))`
    D
    `PV(T_(2) - T_(1))`

    • Similar Questions

    Explore conceptually related problems

    An ideal gas mixture filled inside a balloon expands according to the relation expands according to the relation PV^(2//3)= constant. What will be the temperature inside the balloon

    If gas expands according to relation P = 4 V, then work done in expansion V_o to 3V_o

    One mole of a gas expands with temperature T such thaht its volume, V= KT^(2) , where K is a constant. If the temperature of the gas changes by 60^(@)C then the work done by the gas is 120R

    n moles of an ideal gas undergo a process in which the temperature changes with volume as T=kv^(2) . The work done by the gas as the temperature changes from 7_(0) to 47_(0) is

    One mole of an ideal gas at temperature T_(1) expends according to the law (P)/(V^(2))=a (constant). The work done by the gas till tempereature of gas becomes T_(2) is

    Home
    Profile