Home
Class 11
PHYSICS
Find the centre of gravity of a thin wir...

Find the centre of gravity of a thin wire bent to a semicircle of radius r.

Text Solution

Verified by Experts

The correct Answer is:
At a distance `2r//pi` from the centre
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MOMENT, TORQUE, EQUILIBRIUM OF BODIES

    NN GHOSH|Exercise Exercises|33 Videos

  • LAWS OF MOTION, FREE BODY DIAGRAM

    NN GHOSH|Exercise Exercise (B)|34 Videos

  • ROTATIONAL DYNAMICS, MOMENT OF INERTIA

    NN GHOSH|Exercise Exercises|42 Videos

Similar Questions

Explore conceptually related problems

Using the first Guldin theorem, find the centre of gravity of a semicircle of radius a.

A portion of a conductive wire is bent in the form of a semicircle of radius r as shown below in fig. at centre of semicircle, the magnetic induction will be

Determine the centre of gravity of a thin homogeneous plate having the form of a rectangle with sildes r and 2r from which a semicircle with a radius r is cut out of figure.

Find the centre of gravity of the semicircle x^(2) + y^(2) = a^(2) situated above the x-axis.

Find the coordination of the centre of mass of a uniform semicircular wire of radius R and mass M.

A uniform wire of length l and mass M is bent in the shape of a semicircle of radius r as shown in figure. Calculate moment of intertia about the axis XX'

Find the centre of mass of a thin, uniform disc of radius R from which a small concentric disc of radius r is cut.

Locate c.m. of thin , uniform semicircular wire of radius R .

A straight wire carrying a current of 12A is bent into a semicircular arc of radius 2*0cm as shown in figure. Consider the magnetic field vecB at the centre of arc. (a) What is the magnetic field due to the staight segments? (b) In what way the contribution to vecB from the semicircle differs from that of a circular loop and in what way does it resemble? (c) Would your answer be different if the wire were bent into a semicircle arc of the same radius but in the opposite way as shown in figure

The centre of gravity of a solid hemisphere of radius a is

Home
Profile