The oxidation number of nitrogen atoms in `NH_(4)NO_(3)` are:

Options

A. `+3,+3`
B. `+3,-3`
C. `-3,-5`
D. `-5,+3`

Answer

To find the oxidation numbers of nitrogen atoms in the compound \( NH_4NO_3 \) (ammonium nitrate), we will analyze the oxidation states of nitrogen in both the ammonium ion (\( NH_4^+ \)) and the nitrate ion (\( NO_3^- \)).

### Step-by-Step Solution:

1. **Identify the Ions in the Compound**:
- The compound \( NH_4NO_3 \) consists of two ions: the ammonium ion (\( NH_4^+ \)) and the nitrate ion (\( NO_3^- \)).

2. **Determine the Oxidation State of Nitrogen in \( NH_4^+ \)**:
- The ammonium ion has a charge of +1.
- In \( NH_4^+ \), there are four hydrogen atoms, each with an oxidation state of +1.
- Let the oxidation state of nitrogen be \( X \).
- The equation for the total charge is:
\[ X + 4(+1) = +1 \]
- Simplifying this gives:
\[ X + 4 = 1 \quad \Rightarrow \quad X = 1 - 4 = -3 \]
- Therefore, the oxidation state of nitrogen in \( NH_4^+ \) is **-3**.

3. **Determine the Oxidation State of Nitrogen in \( NO_3^- \)**:
- The nitrate ion has a charge of -1.
- In \( NO_3^- \), there are three oxygen atoms, each with an oxidation state of -2.
- Let the oxidation state of nitrogen be \( Y \).
- The equation for the total charge is:
\[ Y + 3(-2) = -1 \]
- Simplifying this gives:
\[ Y - 6 = -1 \quad \Rightarrow \quad Y = -1 + 6 = +5 \]
- Therefore, the oxidation state of nitrogen in \( NO_3^- \) is **+5**.

4. **Conclusion**:
- In \( NH_4NO_3 \), the oxidation states of nitrogen are:
- Nitrogen in \( NH_4^+ \): **-3**
- Nitrogen in \( NO_3^- \): **+5**

### Final Answer:
The oxidation numbers of nitrogen atoms in \( NH_4NO_3 \) are -3 and +5.