Home
Class 11
PHYSICS
Let a(1) & a(2) are the acceleration of ...

Let `a_(1) & a_(2)` are the acceleration of A & B. Let `b_(1) & b_(2)` the acceleration of C & D relative to the wedges A and B respectively, choose the right relation. (directions of `a_(1), a_(2), b_(1) & b_(2)` are shown in figure below) :

A

`a_(1)-a_(2) +b_(1) -b_(2) =0`

B

`a_(1)+a_(2) - b_(1) - b_(2) =0`

C

`a_(1)+a_(2) + b_(1) + b_(2) =0`

D

`a_(1)+b_(2) = a_(2) + b_(1)`

Text Solution

Verified by Experts

The correct Answer is:
B
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • NEWTONS LAWS OF MOTION

    PHYSICS GALAXY - ASHISH ARORA|Exercise Numerical MCQs|90 Videos
  • NEWTONS LAWS OF MOTION

    PHYSICS GALAXY - ASHISH ARORA|Exercise Advance MCQs|17 Videos
  • NEWTONS LAWS OF MOTION

    PHYSICS GALAXY - ASHISH ARORA|Exercise Discussion Question|39 Videos
  • LINEAR MOMENTUM & ITS CONSERVATION

    PHYSICS GALAXY - ASHISH ARORA|Exercise exercise 1.3|3 Videos
  • RIGID BODIES AND ROTATIONAL MOTION

    PHYSICS GALAXY - ASHISH ARORA|Exercise Unsolved Numerical|63 Videos

Similar Questions

Explore conceptually related problems

Let A = {a_(1), b_(1), c_(1)} and B = {a_(2), b_(2)} (i) A xx B (ii) B xx B

Let (a_(1),b_(1)) and (a_(2),b_(2)) are the pair of real numbers such that 10,a,b,ab constitute an arithmetic progression. Then, the value of ((2a_(1)a_(2)+b_(1)b_(2))/(10)) is

Knowledge Check

  • Let vec( a) _(1) and vec( a) _(2) are the acceleration of wedges A and B. Let vec(b)_(1) and vec(b)_(1) be the accelerations of C and D relative to wedges A and B respectively. Choose the right relation :

    A
    `vec(a)_(1)-vec(a)_(2) +vec(b)_(1)-vec(b)_(2)=0`
    B
    `vec(a)_(1)+vec(a)_(2) +vec(b)_(1)+vec(b)_(2)=0`
    C
    `vec(a)_(1)+vec(a)_(2) -vec(b)_(1)-vec(b)_(2)=0`
    D
    `vec(a)_(1)+2vec(b)_(2) =2vec(a)_(2)-vec(b)_(1)=0`
  • If the equation of the locus of a point equidistant from the points (a_(1),b_(1) , and (a_(2),b_(2)) is (a_(1)-a_(2))x+(b_(1)-b_(2))y+c=0 , then the value of c is

    A
    `1/2(a_(2)^(2)+b_(2)^2)-(a_(1)^(2)-b_(1)^(2))`
    B
    `(a_(1)^(2)-a_(2)^(2)+b_(1)^(2)-b_(2)^(2))`
    C
    `1/2(a_(1)^(2)+a_(2)^(2)+b_(1)^(2)+b_(2)^(2))`
    D
    `sqrt((a_(1)^(2)+b_(1)^(2)-a_(2)^(2)-b_(2)^(2)))`
  • Let a_(1), a_(2),…. and b_(1),b_(2),…. be arithemetic progression such that a_(1)=25 , b_(1)=75 and a_(100)+b_(100)=100 , then the sum of first hundred term of the progression a_(1)+b_(1) , a_(2)+b_(2) ,…. is equal to

    A
    `1000`
    B
    `100000`
    C
    `10000`
    D
    `24000`
  • Similar Questions

    Explore conceptually related problems

    Let a,b,c,d,a in R and satify the relations a(b-c)^(2)+a_(1)bc=c-0 and a(b+c_(1))^(2)+a_(2)bc_(1)+c=1 then which is true

    If the equation of the locus of a point equidistant from the points (a_(1),b_(1)) and (a_(2),b_(2)) is (a_(1)-a_(2))x+(b_(1)-b_(2))y+c=0 then the value of c is

    If the equation of the locus of a point equidistant from the points (a_(1),b_(1)) and (a_(2),b_(2)) is (a_(1)-a_(2))x+(b_(1)-b_(2))y+c=0 then the value of c'is:

    If the equation of the locus of a point equidistant from the points (a_(1),b_(1)) and (a_(2),b_(2)) is (a-1-a_(2))x+(b_(1)-b_(2))y+c=0, then the value of c is

    If the equation (a_(1)-a_(2))x+(b_(1)-b_(2))y=c represents the perpendicular bisector of the segment joining (a_(1),b_(1))(a_(2),b_(2)), then 2c=