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A harmonic oscillation is represented by...

A harmonic oscillation is represented by y=0.34 cos (3000t+0.74), where y and t are in mm and s respectively. Deduce (i) and amplitude (ii) the frequency and angular frequency (iii) the period and (iv) the intial phase.

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To solve the given problem step by step, we will analyze the equation of harmonic oscillation provided: **Given Equation:** \[ y = 0.34 \cos(3000t + 0.74) \] ### Step 1: Identify the Amplitude The standard form of the equation for harmonic motion is: \[ y = A \cos(\omega t + \phi) \] Where: - \( A \) is the amplitude, - \( \omega \) is the angular frequency, - \( \phi \) is the initial phase. From the given equation, we can see that: - Amplitude \( A = 0.34 \) mm. **Solution for Amplitude:** \[ \text{Amplitude} = 0.34 \, \text{mm} \] ### Step 2: Determine the Angular Frequency and Frequency From the equation, we identify the angular frequency \( \omega \): - \( \omega = 3000 \, \text{rad/s} \) To find the frequency \( f \), we use the relationship: \[ \omega = 2\pi f \] Rearranging gives: \[ f = \frac{\omega}{2\pi} \] Substituting the value of \( \omega \): \[ f = \frac{3000}{2\pi} \] Calculating this gives: \[ f \approx \frac{3000}{6.2832} \approx 477.46 \, \text{Hz} \] **Solution for Frequency:** \[ \text{Frequency} \approx 477.46 \, \text{Hz} \] ### Step 3: Calculate the Time Period The time period \( T \) is the reciprocal of the frequency: \[ T = \frac{1}{f} \] Substituting the value of \( f \): \[ T \approx \frac{1}{477.46} \] Calculating this gives: \[ T \approx 0.00209 \, \text{s} \] **Solution for Time Period:** \[ \text{Time Period} \approx 0.00209 \, \text{s} \] ### Step 4: Find the Initial Phase From the equation, the initial phase \( \phi \) is: - \( \phi = 0.74 \) radians. **Solution for Initial Phase:** \[ \text{Initial Phase} = 0.74 \, \text{radians} \] ### Summary of Results 1. **Amplitude:** \( 0.34 \, \text{mm} \) 2. **Frequency:** \( \approx 477.46 \, \text{Hz} \) 3. **Time Period:** \( \approx 0.00209 \, \text{s} \) 4. **Initial Phase:** \( 0.74 \, \text{radians} \) ---
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A harmonic oscillation is represented by y = 0.34 cos(3000 t + 0.74) where y and t are in mm and second respectively. Deduce amplitude, frequency and angular frequency, time period and intianl phase.

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Knowledge Check

  • The equation of a simple harmonic motion is X=0.34 cos (3000t+0.74) where X and t are in mm and sec . The frequency of motion is

    A
    3000
    B
    `3000// 2 pi`
    C
    `0.74 // 2 pi`
    D
    `3000//pi`
  • A wave is represented by y=0.4cos(8t-(x)/(2)) where x and y are in metres and t in seconds. The frequency of the wave is

    A
    `(4)/(pi)s^(-1)`
    B
    `(8)/(pi)s^(-1)`
    C
    `(5)/(pi)s^(-1)`
    D
    `(6)/(pi)s^(-1)`
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