A force of 6.4 N stretches a vertical spring by 0.1m. Find the mass that must be suspended from the spring so that it oscillates with a period of `pi//4`
second.

A force of 6.4N streches a vertical spring by 0.1m The mass that must be supended from the spring so that it oscilation with a time period of pi//4 second

A force of 6.4 N stretches a vertical spring by 0.1 m. The mass (in kg) that must be suspended from the spring so that it oscillates with a time period of (pi)/(4) second.

The scale of a spring balance reading from 0 to 10 kg is 0.25 m long. A body suspended from the balance oscillates vertically with a period of pi//10 second. The mass suspended is (neglect the mass of the spring)

If the period of oscillation of mass M suspended from a spring is one second, then the period of 4M will be

When a mass of 1 kg is suspended from a spring, it is stretched by 0.4m. A mass of 0.25 kg is suspended from the spring and the spring is allowed to oscillate. If g=10 m//s^(2) , then its period of oscillation will be

A mass suspended from a spring of spring constant k is made to oscillate with a time period T. Now, the spring is cut into three equal parts and the mass is suspended from one of the parts. What will be the new time period of oscillations?

When a body is suspended from two light springs separately, the periods of vertical oscillations are T_1 and T_2 . When the same body is suspended from the two spring connected in series, the period will be

A 100 g mass stretches a particular spring by 9.8 cm, when suspended vertically from it. How large a mass must be attached to the spring if the period of vibration is to be 6.28 s?

A block with a mass of 3.00 kg is suspended from an ideal spring having negligible mass and stretches the spring by 0.2 m . (a) What is the force constant of the spring? (b) What is the period of oscillation of the block if it is pulled down and released ?