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If the foot of the perpendicular from the origin to a plane is (2,-3,4), then the equation of the plane is

A

2x+3y+4z=29

B

2x+3y-4z=29

C

2x-3y+4z+29

D

2x-3y-4z=29

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If the foot of the perpendicular from the origin to plane is P(a,b,c), the equation of the plane is a.(x)/(a)=(y)/(b)=(z)/(c)=3bax+by+cz=3cax+by+cz=a^(2)+b^(2)+c^(2)dax+by+cz=a+b+c

The foot of the perpendicular drawn from the origin to a plane is (2, -3, -4). Find the equation of the plane.

Knowledge Check

  • If (2,-1,3) is the foot of the perpendicular down from the origin to the plane, then the equation of the plane is

    A
    `2x+y-3z+6=0`
    B
    `2x-y+3z-14=0`
    C
    `2x-y+3z-13=0`
    D
    `2x+y+3z-10=0`

  • If the foot of the perpendicular drawn from the origin to a plane is (1,2,3), then a point on the plane is

    A
    (3,2,1)
    B
    (7,2,1)
    C
    (7,3,-1)
    D
    (6,-3,4)

  • The coordinate of the foot of perpendicular drawn from origin to a plane is (2,4,-3). The equation of the plane is

    A
    `2x-4y-3z=29`
    B
    `2x-4y+3z=29`
    C
    `2x+4y-3z=29`
    D
    None of these

    • Similar Questions

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    The foot of the perpendicular drawn from the origin to a plane is (1,2,-3). Find the equation of the plane.or If O is the origin and the coordinates of P is (1,2,-3), then find the equation of the plane passing through P and perpendicular to OP.

    The foot of the perpendicular drawn from the origin to a plane is (4,-2,-5) . Find the equation of the plane in (i) vector form, ii) Cartesian form.

    If (2,4,-3)^(@) is the foot of the perpendicular drawn from the origin into a plane,the equations of that plane is

    If the foot of the perpendicular from the origin to a plane E is the point N(1,2,2), then the equation of the plane is

    If the foot of the perpendicular from O(0,0,0) to a plane is P(1,2,2) . Then the equation of the plane is

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