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If the line (x-3)/3 = (y-1)/-2 = (z-c)/-...

If the line `(x-3)/3 = (y-1)/-2 = (z-c)/-8` lies in the plane 2x-y+z=10, then: c=

A

`-3`

B

3

C

`-5`

D

5

Text Solution

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The correct Answer is:
A, B, C, D
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Knowledge Check

  • If the line (x-1)/(2)=(y-1)/(3)=(z+2)/(2) lies in the plane x+By-3z+D=0, then the values of B and D are

    A
    `(4)/(3),(-25)/(3)`
    B
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    C
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    D
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  • If the line (x-1)/(2)=(y-3)/(a)=(z+1)/(3) lies in the plane bx+2y+3z-4=0 , then

    A
    `a=11//2,b=1`
    B
    `a=-5//2,b=-7`
    C
    `a=-11//2,b=1`
    D
    `a=1,b=-11//2`

  • If the line (x-2)/3 =(y-1)/-5 =(z+2)/2 lies in the plane x+3y - alphaz + beta=0 , then: (alpha, beta)-=

    A
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