Home
Class 11
PHYSICS
A particle is projected with velocity 2(...

A particle is projected with velocity `2(sqrt(gh))`, so that it just clears two walls of equal height h which are at a distance of 2h form each other. Show that the time of passing between the walls is `2 (sqrt (h/g)).` [Hint : First find velocity at height h. Treat it as initial velocity and 2h as the range. ]

Text Solution

Verified by Experts

The correct Answer is:
4
Promotional Banner

Topper's Solved these Questions

  • KINEMATICS

    DC PANDEY|Exercise MATCH THE COLUMN|3 Videos

  • GRAVITATION

    DC PANDEY|Exercise (C) Chapter Exercises|45 Videos

  • KINEMATICS 1

    DC PANDEY|Exercise INTEGER_TYPE|15 Videos

Similar Questions

Explore conceptually related problems

A particle is projected with velocity 2 sqrt(gh) so that it just clears two walls of equal height h which are at a distance 2h from each other. Show that the time of passing between the walls is 2 sqrt(h//g) .

A particle is projected with velocity 2 sqrt(gh) so that it just clear two walls of equal height h , which are at a distance of 2h from each other . What is the tiime interval of passing between the two walls ?

An object is projected so that it just clears two walls of height 7.5 m and with separation 50m from each other. If the time of passing between the walls is 2.5s, the range of the projectile will be (g= 10m//s^(2) )

A particle is projected with a velocity u from a point at ground level. Show that it cannot clear a wall of height h at a distance x from the point of projection if u^2 lt g(h+sqrt(h^2+x^2)) .

A particle is projected under gravity with velocity sqrt(2ag) from a point at a height h above the level plane at an angle theta to it. The maximum range R on the grond is :

A particle is projected from the ground at t = 0 so that on its way it just clears two vertical walls of equal height on the ground. The particle was projected with initial velocity u and at angle theta with the horiozontal. If the particle passes just grazing top of the wall at time t = t_1 and t = t_2 , then calculate. (a) the height of the wall. (b) the time t_1 and t_2 in terms of height of the wall. Write the expression for calculating the range of this projectile and separation between the walls.

Knowledge Check

  • A particle is projected with velocity 2 sqrt(gh) so that it just clear two walls of equal height h , which are at a distance of 2h from each other . What is the tiime interval of passing between the two walls ?

    A
    `(2h)/(g)`
    B
    `sqrt((2h)/(g))`
    C
    `sqrt((h)/(g))`
    D
    `2sqrt((h)/(g))`

  • A stone is projected with velocity 2 sqrtgh , so that it just clears two walls of equal height h, at distance of 2h from each other. The time interval of passing between the two walls is

    A
    `sqrt((h)/(g))`
    B
    `sqrt((2h)/(g))`
    C
    `2sqrt((h)/(g))`
    D
    `(2h)/(g)`

  • A particle is projected with velocity 2 sqrt(gh). What will be the time interval for a particle to cross two walls of equal height h separated by a distance of 2h from each other ?

    A
    `(2h)/(g)`
    B
    `sqrt((2h)/(g))`
    C
    `sqrt((h)/(g))`
    D
    `2 sqrt((h)/(g))`