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A particle is projected with velocity 2(...

A particle is projected with velocity `2(sqrt(gh))`, so that it just clears two walls of equal height h which are at a distance of 2h form each other. Show that the time of passing between the walls is `2 (sqrt (h/g)).` [Hint : First find velocity at height h. Treat it as initial velocity and 2h as the range. ]

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A particle is projected with velocity 2 sqrt(gh) so that it just clears two walls of equal height h which are at a distance 2h from each other. Show that the time of passing between the walls is 2 sqrt(h//g) .

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Knowledge Check

  • A particle is projected with velocity 2 sqrt(gh) so that it just clear two walls of equal height h , which are at a distance of 2h from each other . What is the tiime interval of passing between the two walls ?

    A
    `(2h)/(g)`
    B
    `sqrt((2h)/(g))`
    C
    `sqrt((h)/(g))`
    D
    `2sqrt((h)/(g))`

  • A stone is projected with velocity 2 sqrtgh , so that it just clears two walls of equal height h, at distance of 2h from each other. The time interval of passing between the two walls is

    A
    `sqrt((h)/(g))`
    B
    `sqrt((2h)/(g))`
    C
    `2sqrt((h)/(g))`
    D
    `(2h)/(g)`

  • A particle is projected with velocity 2 sqrt(gh). What will be the time interval for a particle to cross two walls of equal height h separated by a distance of 2h from each other ?

    A
    `(2h)/(g)`
    B
    `sqrt((2h)/(g))`
    C
    `sqrt((h)/(g))`
    D
    `2 sqrt((h)/(g))`

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