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A particle is projected with velocity 20...

A particle is projected with velocity `20sqrt(2)m//s` at `45^(@)` with horizontal. After `1s (g=10m//s^(2))` match the following table

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A, B, C
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A particle is projected with velocity 20sqrt(2)m//s at 45^(@) with horizontal. After 1s , find tangential and normal acceleration of the particle. Also, find radius of curveture of the trajectory at that point. (Take g=10m//s^(2))

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Knowledge Check

  • A particle is projected from ground with velocity 40sqrt(2)m//s at 45^(@) . At time t=2s

    A
    displacement of particle is `100m`
    B
    vertical component of velocity is `20m//s`
    C
    velocity makes an angle `tan^(-1)(2)` with vertical
    D
    particle is at height of `60m` from ground

  • A particle is projected from ground with velocity 40sqrt2m at 45^(@) .At time t=2s

    A
    displacement of particles is `100 m`
    B
    vertcal component of velocity is `20 m//s`
    C
    velocity makes an angle of `tan^(-1)(2)` with vertical
    D
    particle is at height of `60 m` from ground

  • A projectile is projected with the initial velocity (6i + 8j) m//s . The horizontal range is (g = 10 m//s^(2))

    A
    `96 m`
    B
    `960 m`
    C
    `9.6 m`
    D
    `4.8 m`

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    A particle is projected with velocity 50 m/s at an angle 60^(@) with the horizontal from the ground. The time after which its velocity will make an angle 45^(@) with the horizontal is

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