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10 g of sample of mixture of CaCl(2) and...

10 g of sample of mixture of `CaCl_(2)` and NaCl are treated to precipitate all the calcium as `CaCO_(3)`. This `CaCO_(3)` is heated to convert all the Ca to CaO and the final mass of `CaCl_(2)` in the original mixture is

A

0.321

B

0.162

C

0.218

D

0.12

Text Solution

Verified by Experts

a) `CaCl_(2) + NaCl = 10g`
Let, weight of `CaCl_(2)` = xg
`CaCl_(2) to CaCO_(3) to CaO`
Moleof CaO = `(1.62)/(56) rArr x/111 = 1.62/56 x = 3.21g`
`%` of `CaCl_(2)` = (3.21/10 x 100) = 32.1%`
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Knowledge Check

  • 10 g of a sample of a mixture of CaCl_(2) and NaCl is treated to precipitate all the calcium as CaCO_(3) . This CaCO_(3) is heated to convert all the Ca to CaO and the final mass of CaO is 1.62 g.The percent by mass of CaCl_(2) in the origial mixture is

    A
    0.321
    B
    0.162
    C
    0.218
    D
    0.11
  • A 10.0 g sample of a mixture of calcium chloride and sodium chloride is treated with Na_(2)CO_(3) to precipitate the calcium as calcium carbonate . This CaCO_(3) is heated to convert all the calcium to CaO and the final mass of CaO is 1.62 gms. The % by mass of CaCl_(2) in the original mixture is

    A
    `15.2 %`
    B
    `32.1 %`
    C
    `21.8 %`
    D
    `11.07 %`
  • A 10.0 g sample of a mxiture of calcium chloride and sodium chloride is treated with Na_(2)CO_(3) to precipitate the calcium as calcium carbonates. This CaCO_(3) is heated to convert all the calcium to CaO and the final mass of CaO is 1.62 gms. The \% by mass of CaCl_(2) in the original mixture is

    A
    `15.2%`
    B
    `32.1%`
    C
    `21.8%`
    D
    `11.07%`
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