In hydrogen atom, an electron jumps from bigger orbit to smaller orbit, so that radius of smaller orbit is one-fourth of radius of bigger orbit. If speed of electron in bigger orbit was v,then speed in smaller orbit is
A
`v/4`
B
`v/2`
C
`v`
D
`2v`
Text Solution
Verified by Experts
The correct Answer is:
D
Radius of nth orbit,`r_(n)propto n^(2)` `(r_("n big"))/r_("n small")=(n^(2)big)/("n^(2)small)=4/1 ` (given) Rightarrow`n_(big)/n_(small)=2` Rightarrow`n_(small)/n_(big)=1/2` Velocity of electron in nth orbit `v_(n)propto1/n` `v_"(n big)"/(v_"(n small)" )=(n_(small))/n_(big)=1/2` Rightarrow`V_"n small"=2(v_"n big")=2v`
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