Silver crystallizes in CCP lattice. The edge length of its unit cell is 408.6 pm. Calculate density of silver (atomic mass of silver is 107.9)

Explanation

Data: Element crystallizes in FCC: `therefore Z=4`
Atomic mass M= 107.9 g
Edge length =a=408.6 pm`=408.6 xx 10^(-12)`m
`=408.6 xx 10^(-12) xx 10^(2)` cm
`=408. 6 xx 10^(-10)` cm
`4.086 xx 10^(-8)` cm
Formula: `d = (Z xx M)/(a^(3) xx N_(A))`
Density (d) = ?
`d=(4 xx 107.9)/((4.086 xx 10^(-4))^(3) xx 6.022 xx 10^(23))`
`d= 431.6/(68.217 xx 10^(-24) xx 6.022 xx 10^(23))`
`d=(431.6)/(41.08) = 10.506 g cm^(-3)`.