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Find the length of seconds pendulum at a...

Find the length of seconds pendulum at a place where `g = pi^(2) m//s^(2)`.

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The correct Answer is:
1 m
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Calculate the length of asecond pendulam at a place where g= 9.8 ms^(-2) . [Hint: A seconds pendulam Is one with a time period of exactly 2 s]

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Knowledge Check

  • The length of a second pendulum is

    A
    99.8 cm
    B
    99 cm
    C
    100 cm
    D
    None of these

  • The length of seconds pendulum at a place wl}ere g = 4.9 m/ s^2 is

    A
    99.54 cm
    B
    60 cm
    C
    50 cm
    D
    101 cm

  • The length of second pendulum is nearly,

    A
    80 cm
    B
    1 m
    C
    2 m
    D
    None of these

    • Similar Questions

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    What is second's pendulum ? Find the length of second's pendulum for g = 9.8 m//s^(2) ? Also write expressions for the time period if the second's pendulum is an a carriage which is accelerating (a) upwards (b) downwards (c ) horizontally. Also, fin the value of time period of it if is made to oscillate a freely falling lift.

    The length of a second’s pendulum at the surface of earth is 1 m. The length of second’s pendulum at the surface of moon where g is 1/6th that at earth’s surface is

    The time period of a simple pendulum is given by T = 2pi sqrt((l)/(g)) where 'l' is the length of the pendulum and 'g' is the acceleration due to gravity at that place. (a) Express 'g' in terms of T (b) What is the length of the seconds pendulum ? (Take g = 10 m s^(-2) )

    A seconds pendulum is shifted from a place where g = 9.8 m//s^(2) to another place where g = 9.78 m//s^(2) . To keep period of oscillation constant its length should be

    The length of a seconds pendulum on the surface of the Earth is 100 cm. Find the length of the seconds pendulum on the surface of the moon. ("Take",g_(M) = (1)/(6)g_(E))

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