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A simple pendulum of length l is suspend...

A simple pendulum of length l is suspended throught the ceiling of an elevator. Find the time period of small oscilations if the elevator a. is going up with an acceleration `a_0`. b. is going down with an acceleration `a_0` and c. is moving with a uniform velocity.

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`(a) 2pisqrt((l)/(a_(0)+g)),(b) 2pisqrt((l)/(g-g_(0))),( c) 2pisqrt((l)/(g))`
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Knowledge Check

  • A simple pendulum of length 1 m is freely suspended from the ceiling of an elevator. The time period of small oscillations as the elevator moves up with an acceleration of 2m//s^2 is (use g=10 m//s^2 )

    A
    `(pi)/sqrt5` s
    B
    `sqrt(2/5)pis`
    C
    `pi/sqrt2` s
    D
    `pi/sqrt3` s

  • A pendulum bob of mass 50 gm is suspended from the ceiling of an elevator. The tension in the string if the elevator goes up with uniform velocity is approximately

    A
    `0.30`N
    B
    `0.40`N
    C
    `0.42` N
    D
    `0.50` N

  • A uniform rod of mass m and length l is suspended about its end. Time period of small angular oscillations is

    A
    `2pi sqrt((l)/(g))`
    B
    `2pi sqrt((2l)/(g))`
    C
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    D
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