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Two waves are represented by y(1)=a(1)...

Two waves are represented by
`y_(1)=a_(1)cos (omega t - kx)` and
`y_(2)=a_(2)sin (omega t - kx + pi//3)`
Then the phase difference between them is-

Text Solution

Verified by Experts

The correct Answer is:
`(pi)/(6)`
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Knowledge Check

  • Two waves are represented by Y_1=a_1 cos (omegat-kx) and Y-2 =a_2 sin (omegat-kx+pi//3) Then the phase difference between them is-

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    `pi/3`
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    `(a_(1)^(2)-a_(2)^(2))`
    B
    `(a_(1)^(2)+a_(2)^(2))`
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