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In a Young’s double slit experiment for ...

In a Young’s double slit experiment for interference of light, the slits are 0.2 cm apart and are illuminated by yellow light `(lambda = 600 nm)`. What would be the fringe width on a screen placed 1 m from the plane of slits if the whole system is immersed in water of index 4/3 ?

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The correct Answer is:
0.225 mm
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In aYoung's double slit experiment for interference of light.the slits are 0.2 cm apart and are illuminated by yellow light (lambda=600nm) .What would be the fringe width on a screen placed 1m from the plane of slits if the whole systems is immersed in water of index 4//3 ?

In Young's experiment for interference of light the slits 0.2 cm apart are illuminated by yellow light (lamda=5896A^(@)) What would be the fringe width on a screen placed 1 m from the plane of slits? What will be the fringe width if the system is immersed in water (refractive index =4//3 )

Knowledge Check

  • Two slits, 4 mm apart, are illuminated by light of wavelength 6000 Å . What will be the fringe width on a screen placed 2 m from the slits

    A
    `0.12 mm `
    B
    `0.3 mm`
    C
    `3.0 mm`
    D
    `4.0 mm`

  • In Young's double-slit experiment, if yellow light is replaced by blue light, the interference fringes become

    A
    Darker
    B
    Brighter
    C
    Wider
    D
    Narrower

  • In young's double slit experiment, the distance between two slits is 0.6 mm and these are illuminated with a light of wavelength 4800 Å. The angular width of first dark fringe on the screen distant 120 cm froms slits will be :

    A
    `8 xx 10^(-4)` rad
    B
    `6 xx 10^(-4)` rad
    C
    `4 xx 10^(-4)` rad
    D
    `16 xx 10^(-4)` rad

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