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The area of the circle x^2+y^2=16 exteri...

The area of the circle `x^2+y^2=16` exterior to the parabola `y^2=6x` is (A) `4/3(4pi-sqrt(3))` (B) `4/3(4pi+sqrt(3))`(C) `4/3(8pi-sqrt(3))` (D) `4/3(8pi+sqrt(3))`

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To find the area of the circle \(x^2 + y^2 = 16\) that is exterior to the parabola \(y^2 = 6x\), we will follow these steps: ### Step 1: Identify the equations The equation of the circle is: \[ x^2 + y^2 = 16 \] The equation of the parabola is: ...
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