The total revenue in Rupees received from the sale of x units of a product is given by `R(x)=3x^2+36 x+5`. The marginal revenue, when `x = 15`is (A) 116 (B) 96 (C) 90 (D) 126

Explanation

To find the marginal revenue when \( x = 15 \) for the total revenue function \( R(x) = 3x^2 + 36x + 5 \), we will follow these steps:

### Step 1: Differentiate the Revenue Function
We need to find the derivative of the revenue function \( R(x) \) with respect to \( x \). The marginal revenue \( MR \) is given by:
\[ MR = \frac{dR}{dx} \]
Differentiating \( R(x) \):
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