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Prove that, 3[sin^(4)((3pi)/2 - alpha) +...

Prove that, `3[sin^(4)((3pi)/2 - alpha) + sin^(4)(3pi + alpha)] - 2[sin^(6)((pi)/2 + alpha) + sin^(6) (5pi - alpha)] = 1`

Answer

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Show that 3{sin^4((3pi)/2-alpha)+sin^4(3pi+alpha)}-2{sin^6(pi/2+alpha)+ sin^6(5pi-alpha)}=1

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Knowledge Check

  • The expression 3{sin^4((3pi/2)-alpha)+sin^4(3pi-alpha)} -2{sin^6(pi/2+alpha)+sin^6(5pi-alpha)} is equal to

    A
    0
    B
    1
    C
    3
    D
    `sin 4alpha=cos 6alpha`

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