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sin alpha + sin beta = a "and" cos alpha...

`sin alpha + sin beta = a "and" cos alpha + cos beta = b`
`sin (alpha + beta) =`

A

`(2ab)/(a^(2) + b^(2))`

B

`(2ab)/(a^(2) - b^(2))`

C

`(a^(2) + b^(2))/(2ab)`

D

`(a^(2) - b^(2))/(2ab)`

Text Solution

Verified by Experts

The correct Answer is:
A
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