Home
Class 12
CHEMISTRY
One mole of A present in a closed vessel...

One mole of A present in a closed vessel undergoes decays as:
`._(Z)A^(m) rarr ._(Z - 4)B^(m - 8) + 2 (._(2)He^(4))`
What will be the volume of helium gas collocted at `STP` afterd 20 days `(t_(1//2) "of" A = 10` days)?

Answer

Step by step text solution for One mole of A present in a closed vessel undergoes decays as: ._(Z)A^(m) rarr ._(Z - 4)B^(m - 8) + 2 (._(2)He^(4)) What will be the volume of helium gas collocted at STP afterd 20 days (t_(1//2) "of" A = 10 days)? by CHEMISTRY experts to help you in doubts & scoring excellent marks in Class 12 exams.

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CLASSROOM PROBLEMS

    MOTION|Exercise Solid State|18 Videos

  • CLASSROOM PROBLEMS

    MOTION|Exercise Mole Concept|29 Videos

  • CLASSROOM PROBLEMS

    MOTION|Exercise Chemical Equilibrium|38 Videos

  • Chemical Kinetics

    MOTION|Exercise Exercise - 4 (Level - II) (SUBJECTIVE PROBLEM)|1 Videos

  • CLASSROOM PROBLEMS 1

    MOTION|Exercise THERMODYNAMICS|17 Videos

Similar Questions

Explore conceptually related problems

One mole of X present in a closed vessel undergoes decays as: ._(Z)X^(A) rarr ._(Z - 2)Y^(A - 4) + (._(2)He^(4)) What will be the volume of helium gas collected as SATP and STP (1 bar pressures, 273 K temperature) after 20 days (t_(1//2) "of" A = 10 days)?

A certain radio isotope ._(Z)X^(A) (half life = 10 days) decays to give ._(Z-2)Y^(A-4) . If 1.0 g atom of X is kept in a sealed vessel, find the volume of helium accumulated at STP in 20 days ?

Knowledge Check

  • One mole of A present in a closed vessel undergoes decay as: ._(Z)^(A) rarr ._(Z-4)^(m-8)B + 2 ._(2)^(4)He . The volume of He collected at NTP after 20 day ( t_(1//2) for A = 10 day) is:

    A
    `11.2` litre
    B
    `22.4` litre
    C
    `33.6` litre
    D
    `67.2` litre

  • One mole of a present in a closed vessel undergoes decay as ""_(z)""^(m)Ato""_(Z-4)""^(m-8)B+2""_(2)""^(4)He . The volume of He collected at NTP a fter 20 days is ( t""_(1//2)=10 days)

    A
    11.2 litre
    B
    22.4 litre
    C
    33.6 litre
    D
    67.2 litre

  • ._(Z)X^(M) + ._(2)He^(4) rarr ._(15)P^(30) + ._(0)n^(1) . Then

    A
    `Z = 12, M = 27`
    B
    `Z = 13, M = 27`
    C
    `Z = 12, M = 17`
    D
    `Z = 13, M = 28`

    • Similar Questions

    Explore conceptually related problems

    A certain radioisotope ""_(Z)^(A)X ( t_((1)/(2))=10 days) decays to give ""_(Z-2)^(A-4)Y . If 1 mole of ""_(Z)^(A)X is kept in a sealed vessel, what volume of helium will accumulate in 20 days at NTP?

    What is the value of decay constant of a compound having half-life time T_(1//2) = 2.95 days

    In a nuclear decay ""_(Z)X^(A) to ""_(z-1)M^(A-4) to ""_(z-2)N^(A-4) the particles emitted are in sequence:

    A certain radioactive isotope ._(Z)^(A)X(t_(1//2)=100 days decays to ._(Z-2)^(A-8)Y . If 1 mole of ._(Z)^(A)X is kept in sealed container , how much He gas will accumulate at STP in 200 days?

    The two nuclides z^(A^(m)) and ""_(z-2)B^(m-4) are known as

    Home
    Profile