Home
Class 12
MATHS
Let f(x)=|x|+|sinx|, x in (-pi/ 2,3pi/2)...

Let `f(x)=|x|+|sinx|, x in (-pi/ 2,3pi/2).` Then , `f` is

A

conti. no where

B

conti. every where

C

differentiable no where

D

Differentiable every where except at x = 0

Text Solution

Verified by Experts

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • DIFFERENTIABILITY

    MOTION|Exercise Exercise - 3 | Subjective | JEE Advanced|10 Videos
  • DIFFERENTIABILITY

    MOTION|Exercise Exercise - 4 | Level-I Previous Year | JEE Main|15 Videos
  • DIFFERENTIABILITY

    MOTION|Exercise Exercise - 2 (Level-I) Objective Problems | JEE Main|15 Videos
  • DETERMINANTS

    MOTION|Exercise EXERCISE-4 (LEVEL-II)|6 Videos
  • DIFFERENTIAL EQUATION

    MOTION|Exercise Exercise 4|29 Videos

Similar Questions

Explore conceptually related problems

Let f(x)=[3+2cos x],x in(-(pi)/(2),(pi)/(2)) where [.] is the GIF .Then the number of points of discontinuity of f(x) is

f(x) = sinx - sin2x in [0,pi]

Knowledge Check

  • Let f(x)=|x|+|sin x|, x in (-pi//2,pi//2). Then, f is

    A
    nowhere continuous
    B
    continuous and differentiable everywhere
    C
    nowhere differentiable
    D
    differentiable everywhere except at x=0
  • Let f(x)= sinx - tanx, x in (0, pi//2) then tangent drawn to the curve y= f(x) at any point will

    A
    lie above the curve
    B
    lie below the curve
    C
    nothing can be said
    D
    be parallel to a fixed line.
  • Let f(x)=2sinx+tax-3x Statement-1: f(x) does not attain extreme in (-pi//2,pi//2) Statement-2 : f(x) is strictly increasing on (-pi//2,pi//2)

    A
    Statement-1 is True, Statement-2 is True,Statement -2 is a correct explanation for Statement -4
    B
    Statement -1 True ,Statement -2 is True ,Stament -2 is not a correct explanation for Statement -!
    C
    Statement -1 is True Statement -2 is False
    D
    Statement -1 is Flase,Statement -2 is True
  • Similar Questions

    Explore conceptually related problems

    Let f(x)=min{1,cos x,1-sinx}, -pi le x le pi , Then, f(x) is

    Let f(x)=sin x+2cos^(2)x,x in[(pi)/(6),(2 pi)/(3)] then maximum value of f(x) is

    If f(x)=|cosx-sinx|, then f'(pi)/(2) is equal to

    Let f(x) {(-2sinx,- pi le x le - pi/2),(a sin x+b ,-pi/2 le x le pi/2),(cosx,pi/2 le x le pi):}

    Let f(x) {(-2sinx,- pi le x le - pi/2),(a sin x+b ,-pi/2 le x le pi/2),(cosx,pi/2 le x le pi):}