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One mole of an ideal gas undergoes a pro...

One mole of an ideal gas undergoes a process `p=(p_(0))/(1+((V_(0))/(V))^(2))`. Here, `p_(0)` and `V_(0)` are constants. Change in temperature of the gas when volume is changed from `V=V_(0)` to `V=2V_(0)` is

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The correct Answer is:
`(11P_0V_0)/(10R)`
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