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Find the shortest distance between the lines`(x+1)/7=(y+1)/(-6)=(z+1)/1`and `(x-3)/1=(y-5)/(-2)=(z-7)/1`

Answer

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Find the shortest distance between the lines (x+1)/(7)=(y+1)/(-6)=(z+1)/(1)(x-3)/(1)=(y-5)/(-2)=(z-7)/(1)

Find the length and the equations of the line of shortest distance between the lines (x+1)/(7)=(y+1)/(-6) =(z+1)/(1) " and " (x-3)/(1)=(y-5)/(-2) =(z-7)/(1)

Knowledge Check

  • The shortest distance between the lines (x+1)/(7)=(y-1)/(-6)=(z+1)/(1) and (x-3)/(1)=(y-5)/(-2)=(z-7)/(1) is

    A
    `sqrt(29)` units
    B
    29 units
    C
    `29/2` units
    D
    `2sqrt(29)` units

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    Find the shortest distance between the lines (x-6)/(3)=(y-7)/(-1)=(z-4)/(1) and (x)/(-3)=(y-9)/(2)=(z-2)/(4)

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    Equation of the line of the shortest distance between the lines (x)/(1)=(y)/(-1)=(z)/(1) and (x-1)/(0)=(y+1)/(-2)=(z)/(1) is:

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    Find the magnitude of the shortest distance between the lines (x)/(2)=(y)/(-3)=(z)/(1) and (x-2)/(3)=(y-1)/(-5)=(z+2)/(2) .

    Equation of the line of the shortest distance between the lines (x)/(2)=(y)/(-3)=(z)/(1) and (x-2)/(3)=(y-1)/(-5)=(z+2)/(2) is

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