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How is XeF(6) prepared from the XeF(4) ?...

How is `XeF_(6)` prepared from the `XeF_(4)` ? Write the chemical equation for the reaction.

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To prepare `XeF_(6)` from `XeF_(4)`, we need to oxidize `XeF_(4)` to `XeF_(6)`. The oxidation state of xenon in `XeF_(4)` is +4, and in `XeF_(6)`, it is +6. To achieve this oxidation, we can use an oxidizing agent. ### Step-by-Step Solution: 1. **Identify the Reactants and Products**: - Reactant: `XeF_(4)` - Product: `XeF_(6)` - Oxidizing Agent: `O_2F_2` (dioxygen difluoride) ...
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