Home
Class 11
PHYSICS
(a) Pressure decreases as one ascends th...

(a) Pressure decreases as one ascends the atmosphere. If the density of air is `rho,` What is the change in pressure dp over a differential height dh ? (b) Considering the pressure p to be proportional to the density, find the pressure p at a height h if the pressure on the sureface of the earth is `p_0.` (c ) If `p_0 = 1.03 xx 10^5 Nm^(-2), rho_0 = 1.29kg m^(-3) and g = 9.8 ms^(-2), ` at what height will the pressure drop to `(1//10)` the value at the surface of the earth ? (d) This model of the atmosphere works for relatively small distance. Identify the underlying assumption that limits the model.

Text Solution

Verified by Experts

Consider a horizontal parcel of air with cross-section A and height dh.

Let the pressure on the top surface and bottom surface be p and p+ dp. If the parcel is in equilibrium , then the net upward force must be balanced by the weight.
i.e., `(p+dp)A-pA=-rhogAdh" "(because` weight =Density `xx` Volume `xx g )`
`=-rhoxxAdh xx g`
`implies dp =-rhogdh. " "(rho=` density of air `)`
Negative sign shows that pressure decreases with height .
(b) Let `p_(@)` be the density of air on the surface of the earth.
As per question, pressure `prop` density
`implies (p)/(p_(@))=(rho)/(rho_(@))`
`implies rho=(rho_(@))/(p_(@))pdh" "[because dp=-rhogdh]`
`implies (dp)/(p)=-(rho_(@)g)/(p_(@))dh`
`implies underset(p_(@))overset(p)int (dp)/(p)=-(rho_(@)g)/(p_(@))underset(0)overset(h)int dh " "{:[(because "at h" =0, r=p_(@)),("and at h" =h,p=p)]:}`
`implies "In" (p)/(p_(@))=-(rho_(@)g)/(p_(@))h`
By removing log, `p=p_(@)e(-(rho_(@)gh)/(p_(@)))`
(c) As `p=p_(@)e^(-(rho_(@)gh)/(p_(@)))`,
`implies "In" (p)/(p_(@))=-(rho_(@)gh)/(P_(@))`
By question,
`p=(1)/(10)p_(@)`
`implies "In"(((1)/(10)p_(@))/(p_(@)))=-(rho_(@)g)/(p_(@))h`
`implies "In"(1)/(10)=-(rho_(@)g)/(p_(@))hrho_(@)`
`h=-(p_(@))/(rho_(@)g)"In"(1)/(10)=-(p_(@))/(p_(@)g)"In"(10)^(-1)=(p_(@))/(p_(@)g)"In"10`
`=(p_(@))/(rho_(@)g)xx2.303" "` [`because` In `(x)=2.303 "log"_(10)(x)]`
`=(1.013xx10^(5))/(1.22xx9.8)xx2.303=0.16xx10^(5)`m
`=16xx10^(3) `m
(d) We know that `" "p prop rho` (when T=constant i.e., isothermal pressure)
Temperature (T) remains constant only near the surface of the earth , not at greater heights.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MECHANICAL PROPERTIES OF FLUIDS

    NCERT EXEMPLAR|Exercise Short Answer Type Questions|5 Videos
  • LAWS OF MOTION

    NCERT EXEMPLAR|Exercise Long answer Type Questions|9 Videos
  • MECHANICAL PROPERTIES OF SOLIDS

    NCERT EXEMPLAR|Exercise LONG SHORT ANSWER TYPE QUESTION|16 Videos

Similar Questions

Explore conceptually related problems

The pressure of confined air is p. If the atmospheric pressure is P, then :-

The density of air at one atmospheric pressure is 0.9kgm^(-3) What will be its density at 4 atmospheric pressure,when temperature remains constant?

Knowledge Check

  • The pressure at depth h below the surface of a liquid of density rho open to the atmosphere is

    A
    greater than the atmospheric pressure by `rhogh`
    B
    less than the atmospheric pressure by `rhogh`
    C
    equal to the atmospheric pressure
    D
    increases exponentially with depth
  • It P is the pressure and rho is the density of a gas, then P and rho are realted as :

    A
    `P prop rho`
    B
    `P prop rho^(2)`
    C
    `P prop 1//rho`
    D
    `P prop 1//rho^(2)`
  • If P is the pressure of a gas and rho is its density , then find the dimension of velocity in terms of P and rho .

    A
    `P^(1//2) rho^(-1//2)`
    B
    `P^(1//2) rho^(1//2)`
    C
    `P^(-1//2) rho^(-1//2)`
    D
    `P^(-1//2) rho^(-1//2)`
  • Similar Questions

    Explore conceptually related problems

    The density of air at one atmospheric pressure is 0.9kgm^(-3) What will be its density at "4" atmospheric pressure,when temperature remains constant?

    If the atompspheric pressure is P _(a) then the jpressure P at depth a below the surface of a liquid of density rho open to the atmosphere is

    If P is the pressure and d is the density of gas, then P and d are related as :

    In the given figure, atmospheric pressure p_0 = 1 atm and mercury column length is 9 cm. Pressure p of the gas enclosed in the tube is

    A beaker is filled with a liquid of density rho upto a height h If the beaker is at rest, the mean pressure at the walls is: