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The young's modulus for steel is much mo...

The young's modulus for steel is much more then that for rubber. For the same longitudinal strain, which one will have greater tensil stress ?

Text Solution

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Young's modulus (Y) = `("Stress")/("Longitudinal strain")`
For same longitudinal strain, `" Y "prop` stress
`therefore " "(Y_("steel"))/(Y_("rubber"))=(("stress")_("steel"))/(("stress")_("rubber"))" ....(i)"`
But `" "Y _("steel")gtY_("rubber")`
`therefore" "(Y_("steel"))/(Y_("rubber"))gt1`
Therefore, from Eq. (i),
`" "(("stress")_("steel"))/(("stress")_("rubber")) gt 1`
`implies " "("stress")_("steel") gt ("stress")_("rubber")`
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Knowledge Check

  • The ratio of tensile stress to the longitudinal strain is defined as

    A
     bulk modulus
    B
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    shear modulus
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    compressibility

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