X and Y are two volatile liquids with mo...

`X` and `Y` are two volatile liquids with molar weights of `10gmol^(-1)` and `40gmol^(-1)` respectively. Two cotton plugs, one soaked in `X` and the other soaked in `Y`, are simultaneously placed at the ends of a tube of length `L=24` cm, as shown in the figure.
The tube is filled with an inert gas at 1 atm pressure and a temperature of `300K`. Vapours of `X` and `Y` react to form a product whichh is first observed at a distance `d`cm from the plug soaked in `X`.
Take `X` and `Y` to have equal molecular diameters and assume ideal behaviour for the inert gas and two vapours.

The value of `d` in cm (shown in figure), as estimated from Graham's law, is

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The correct Answer is:

`(r_(X))/(r_(Y)) = (d)/((24 - d)) = sqrt((40)/(10)) = 2` On solving, `d = 16 cm`

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X and Y are two volatile liquids with molar weights of 10gmol^(-1) and 40gmol^(-1) respectively. Two cotton plugs, one soaked in X and the other soaked in Y , are simultaneously placed at the ends of a tube of length L=24 cm, as shown in the figure. The tube is filled with an inert gas at 1 atm pressure and a temperature of 300K . Vapours of X and Y react to form a product whichh is first observed at a distance d cm from the plug soaked in X . Take X and Y to have equal molecular diameters and assume ideal behaviour for the inert gas and two vapours. The experimental value of d is found to be smaller than the estimate obtained using Graham's law. This is due to

larger mena free path for `X` as a compared of that of `Y`

larger mean free path for `Y` as compared to that of `X`

increased collision frequency of `Y` with the inert gas as compared to that of `X` with the inert gas

increased collision frequency of `X` with the inert gas as compared to that of `Y` with the inert gas

III

White solid does not formed

directly proportional to their densities

inversely proportional to their densities

directly proportional to square of their densities

inversely proportional to square of theire densities.