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KCl crystallises in the same type of lat...

KCl crystallises in the same type of lattice as does NaCl Given that `r_(Na^(+))//r_(Cl^(-))=0.55` and `r_(K^(+))//r_(Cl^(-))=0.74`, the ratio of the side of unit cell for KCl to that of NaCl is

A

1.123

B

0.891

C

1.414

D

1.112

Text Solution

Verified by Experts

The correct Answer is:
A
`(r_(Na^(+)))/(r_(Cl^(-)))=0.55,(r_(K^(+)))/(r_(Cl^(-)))=0.74`
`(r_(Na^(+)))/(r_(Cl^(-)))+1=1.55" "...(1)`
`(r_(Na^(+)))/(r_(Cl^(-)))+1=1.74" "...(2)`
Dividing (2) by (1)
`(1.74)/(1.55)=(r_(K^(+))+r_(Cl^(-)))/(r_(Cl^(-)))xx(r_(Cl^(-)))/(r_(Na^(+))+r_(Cl^(-)))`
`(r_(K^(+))+r_(Cl^(-)))/(r_(Na^(+))+r_(Cl^(-)))=1.122`
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KCl crystallises in the same type of lattices as does NaCl. Given that r_(Na^(+)) //r_(Cl^(-)) = 0.55 and r_(K^(+)) //r_(Cl^(-)) = 0.74 . Calculate the ratio of the side of the unit cell of KCl to that of NaCl.

KCl Crystallizes in the same type of lattice as does NaCl. Given that, (r_(Na^(+)))/(r_(Cl^(-)))=0.5 and (r_(Na^(+)))/(r_(K^(+)))=0.7 Calculate : (a) The ratio of the side of unit cell for KCl to that for NaCl and (b) The ratio of density of NaCl to that for KCl.

Knowledge Check

  • KCl Crystallises in the same type of lattice as does NaCl. Given that (r_(NA^(+)))/(r_(Cl))=0.55 and (r_(K^(+)))/(r_(Cl^(-)))=0.74 . The ratio of the side of the unit cell of KCl to that of NaCl is :

    A
    `1.123`
    B
    `0.891`
    C
    `1.414`
    D
    `10.414`

  • KCl crystallises in the same type of lattice does NaCl. Given that r_(Na+)//r_(Cl^(-))=0.55 and r_(K+)//r_(Cl^(-))=0.74 . Determine the ratio of the side of the unit cell for KCl to that of NaCl

    A
    0.124
    B
    1.123
    C
    0.891
    D
    1.414

  • KCl crystallises in the same type of lattice as does NaCl. Given that r_(Na^+)//r_(Cl^-) =0.55 and r_(K^+)// r_(Cl^-) =0.74 . Calculate the ratio of the side of the unit cell of KCl to that of NaCl

    A
    1.123
    B
    0.891
    C
    1.414
    D
    0.414

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