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The units of ionic product of water (K(w...

The units of ionic product of water `(K_(w))` are

A

`mol^(-1) L^(-1)`

B

`mol ^(-2) L^(-2)`

C

`mol^(-2) L^(-1)`

D

`mol^(2)L^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
D

`K_(w)=[H^(+)][OH^(-)]`
Units of `K_(w)=(mol L^(-1))(mol L^(-1))`
`=mol^(2)L^(-2)`
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Specific conductance of pure water at 25^(@)C is 0.58 xx 10^(-7) "mho cm"^(-1) . Calculate ionic product of water (K_(w)) if ionic conductances of H^(+) and OH^(+) ions at infinite dilution are 350 and 198 mho cm^(2) respectively at 25^(@)C .

What is meant by ionic product of water ?

Knowledge Check

  • The unit of ionic product of water K_(w) are

    A
    `Mol^(-1) L^(-1)`
    B
    `Mol^(-2) L^(-2)`
    C
    `Mol^(-2) L^(-1)`
    D
    `Mol^(2) L^(-2)`
  • The unit of Ionic product of water (kw) is: जल के आयोनिक गुणनफल (kw) का एकक है:-

    A
    `"Mol"^2 "lit"^(-1)`
    B
    `"Mol"^2 "lit"^(-2)`
    C
    `"Mol"^(-1) "lit"^(-2)`
    D
    `"Mol"^(-1) "lit"^(-1)`
  • Approximate relationship between dissociation constant of water (K) and ionic product of water (K_(w)) is

    A
    `K_(w) = K`
    B
    `K_(w) = 55.6 xx K`
    C
    `K_(w) = 18 xx K`
    D
    `K_(w) = 14 xx K`
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