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13.5 gmof aluminium when changes to Al^(...

13.5 gmof aluminium when changes to `Al^(+3)` ion in solution, will lose: `[Ai = 27, N_(A) = 6 xx 10^(23)]`

A

`18.0xx10^23` electrons

B

`6.023xx10^23` electrons

C

`3.01 xx 10^23` electrons

D

`9.1xx10^(23)` electrons

Text Solution

Verified by Experts

The correct Answer is:
D
13.5 g of Al=13.5/27=0.5 mol of Al
`Al to Al^(3+)+3e^-`
3 moles of electrons are lost by 1 mole of Al.
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Knowledge Check

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