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The curves obtained when molar conductiv...

The curves obtained when molar conductivity `lambda_(m)` (along Y-axis) is plotted against the square root of concentration `C^(1//2)` (along X-axis) for two electrolytes 'A' and 'B' are shown.

(a) What can you say about the nature of the two electrolytes ?
(b) How do you account for the increase in molar conductivity `Lambda_(m)` for the electrolytes A and B on dilution ?

Text Solution

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(a) Electrolyte 'A' is a strong while 'B' is a weak electrolyte.
(b) In case of strong electrolyte, 'A', the ionisation is already complete. With dilution, the interionic forces decrease. Therefore, the ionic mobility increases leading to small increase in the value of `Lambda_(m)`. This continues till limiting value of molar conductance reaches. It is denoted either as `Lambda^(0)` or as `Lambda^(oo)`. In case of weak electrolyte, 'B' the extent of dissociation is very small. It increase with dilution. As a result, the value of `Lambda_(m)` increases with dilution. Since there is an enormous increase in ionisation upon dilution, there is large increase in the value of `Lambda_(m)` when the solution is very dilute. This has been depicted in the curve. In case of electrolyte 'B', the limiting value of the molar conductance (`Lambda_(m)^(0)`) cannot be achieved since the dissociation of the electrolyte is never complete.
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The following curve is obtained when molar conductivity Lambda_(m) is plotted against the square root of concentration C^(1//2) (x-axis) for two electrolytes A and B : (a) What can you say about the nature of the two electrolytes A and B ? (b) How do you account for the increase in molar conductivity A, for the electrolytes A and B on dilution ?

The following curve is obtained when molar conductivity (wedge_(m)) is plotted against the square root of concentration, c^(1//2) for two electrolytes A and B (a) How do you account for the increase in the molar conductivity of the electrolyte A on dilution. (b) As seen from the graph, the value of limiting molar conductivity (wedge_(m)^(0)) for electrolyte B cannot be obtained graphically. How can this value be obtained?1

Knowledge Check

  • According to Kohlrausch law, the limiting molar conductivity of an electrolyte, A_(m)B_(n) , can be expressed as

    A
    `Lambda_(m)^(0)=m_(+)lambda_(A^(n+))^(0)-n_lambda_(B^(m-))^(0)`
    B
    `Lambda_(m)^(0)=m_(+)lambda_(A^(m+))^(0)+n_lambda_(B^(n-))^(0)`
    C
    `Lambda_(m)^(0)=n_(+)lambda_(A^(m+))^(0)-m_lambda_(B^(n-))^(0)`
    D
    `Lambda_(m)^(0)=m_(+)lambda_(A^(n+))^(0)-n_lambda_(B^(m-))^(0)`
  • Molar conductance Lamda_(m) is plotted against sqrt(C) (mol "litre"^(-1) ) for three electrolytes (NaCl, HCl, NH_(4)OH) which of the following is correct ?

    A
    `{:(1,2,3,),(NaCl,HCl,NH_(4)OH,):}`
    B
    `{:(1,2,3,),(HCl,NaCl,NH_(4)OH,):}`
    C
    `{:(1,2,3,),(NH_(4)OH,NaCl,HCl,):}`
    D
    `{:(1,2,3,),(NH_(4)OH,HCl,NaCl,):}`
  • Statement: For a weak electrolyte, the plot of molar conductivity (Lambda_(m)) against sqrt(C )(C is concentration in mol litre^(-1)) is nearly linear. Explanation: The molar conductivity at infinite dilution (Lambda_(m)) for an electrolyte can be considered equal to the sum of the limiting molar conductivities of the individual ions.

    A
    S is correct but E is wrong.
    B
    S is wrong but E is correc.
    C
    Both S and E are correct and E is correct explanation of S.
    D
    Both S and E are correct but E is correct explanation of S.
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