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Using crystal field theory, draw energy ...

Using crystal field theory, draw energy level diagram, write electronic configuration of the central metal atom/ion and determine the magnetic moment value in the following
(a) `[CoF_(6)]^(3-), [Co(H_(2)O)_(6)]^(2+), [Co(CN)_(6)]^(3-)`
(b) `FeF_(6)^(3-), [Fe(H_(2)O)_(6)]^(2+), [Fe(CN)_(6)]^(4-)`

Text Solution

Verified by Experts

The magnetic moment value is linked with the number of unpaired which depends upon the position of the ligands. In the electrochemical series i.e., whether it is a weak field ligand or strong field ligand. Ini the light of the above observation, the magnetic moment values of the compounds are calculated:
i) `[CoF_(6)]^(3-)`: `F^(-)` ion is a weak field ligand. The value of `Delta_(0)` is small `(Pgt Delta_(0))`. Electron pairing is not possible.

Number of unpaired electrons = 4
Magnetic moment = `sqrt(n(n+2))=sqrt(4(4+2)) = sqrt(24)= 4.9BM`
ii) `[Co(H_(2)O)_(6)]^(2+)`: `H_(2)O` is a weak field ligand. The value of `Delta_(0)` is small (Pgt`Delta_(0))`. Electron pairing is not possible.
ltbr. Number of electrons = 3
`sqrt(n(n+2))=sqrt(3(3+2)) = sqrt(15)= 3.87BM`
iii) `[Co(CN)_(6)]^(3-)` : `CN^(-)` is a strong field ligand. The value of `Delta_(0)` is large (P lt`Delta_(0))`. Electron pairing is not possible.

Number of unpaired electrons = Zero.
Since there are no unpaired electrons present, the complex is diamagnetic in nature.
`[FeF_(6)]^(3-)` : `F^(-)` ion is a weak ligand. The value of `Delta_(0)` is small `(P gt Delta_(0))`. Electrons pairing is not possible.

Number of unpaired electrons = 5
`sqrt(n(n+2))=sqrt(5(5+2)) = sqrt(35)= 5.92BM`
v) `[Fe(H_(2)O)_(6)]^(2+)` : `H_(2)O` is a weak field ligand. The value of `Delta_(0)` is small `(Pgt Delta_(0))`. Electrons pairing is not possible.

Number of unpaired electrons = 4
Magnetic moment = `sqrt(n(n+2))=sqrt(4(4+2)) = sqrt(24)= 4.9BM`
`[Fe(CN)_(6)]^(4-)` : `CN^(-)` ion is a strong field ligand. The value of `Delta_(0)` is large `(P lt Delta_(0))`. Electron pairing is possible.

Number of unpaired electrons= zero.
Since there are no unpaired electrons present, the complex is diamagnetic in nature.
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Using crystal field theory, draw energy level diagram, write electronic configuration of the central metal atom/ion and determine the magnetic moment value in the following : (i) [CoF_(6)]^(3-),[Co(H_(2)O)_(6)]^(2+),[Co(CN)_(6)]^(3-) (ii) [FeF_(6)]^(3-),[Fe(H_(2)O)_(6)]^(2+),[Fe(CN)_(6)]^(4-)

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Knowledge Check

  • [Fe(H_(2)O)_(6)]^(2+) and [Fe(CN)_(6)]^(4-) differ in

    A
    geometry, magnetic moment
    B
    geometry, hybridization
    C
    magnetic moment, colour
    D
    hybridisation, number of d - electrons
  • [Fe(H_(2)O)_(6)]^(2+) and [Fe(CN)_(6)]^(4-) differ in:

    A
    geometry, magnetic moment
    B
    geometry, hybridization
    C
    magnetic moment, colour
    D
    hybridization number of d-electrons
  • [Fe(H_(2)O)_(6)]^(2+) and [Fe(CN)_(6)]^(4-) differ in :

    A
    geometry, magnetic moment
    B
    geometry, hybridization
    C
    magnetic moment, colour
    D
    hybridization, number of `d-` electrons
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