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Water falls from a tap with A(0)=4 m^(2)...

Water falls from a tap with `A_(0)=4 m^(2)`, `A=1 m^(2)` and h=2 m, then velocity v is

A

`2.5 ms^(-1)`

B

`6.5 ms^(-1)`

C

`4.5 ms^(-1)`

D

`1.5 ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
Given, `(v^(2))/(2g)=h=10 cm`
`therefore " " v=sqrt(2gh)=sqrt(2xx10xx0.1)=sqrt(2) ms^(-1)`
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