The photon radiated from hydrogen corres...

The photon radiated from hydrogen corresponding to `2^(nd)` of Lyman series is abosorbed by a hydrogen like atom `'X'` in `2^(nd)` excited state. As a result the hydrogen like atom `'X'` makes a transition to `n^(th)` orbit. Then :

`X = He^(+), n = 4`

`X = Li^(++), n = 6`

`X = He^(+), n = 6`

`X = Li^(++), n = +9`

Verified by Experts

The correct Answer is:

`13.6[1/1 - 1/9] = 13.6Z^(2)(1/9 - 1/(n^(2)))`

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The photon radiated from hydrogen corresponding to the second line of Lyman series is absorbed by a hydrogen like atom X in the second excited state. Then, the hydrogen-like atom X makes a transition of nth orbit.

`X = He^(+) , n = 4`

`X = Li^(+ +) , n = 6`

`X = He^(+) , n = 6`

`X = Li^(+ +) , n = 9`

`r_(0)`

`pir_(0)`

`3pir_(0)`

`6pir_(0)`

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