When a hydrogen atom is excited from gr...

When a hydrogen atom is excited from ground state to first excited state then

Its kintic energy increases by `10.2 eV`

Its kinetic energy decreases by `10.2 eV`

It potential energy increases by `20.4 eV`.

Its angular momentum increases by `1.05 xx 10^(34) J-s`

Text Solution

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The correct Answer is:

B, C, D

`|DeltaK| = 13.6[(1)/(1^(2)) - (1)/(2^(2))] = 10.2 eV` ltbr gt `|DeltaU| = 27.2 [(1)/(1^(2)) - (1)/(2^(2))] = 20.4eV`
`DeltaL = (2h)/(2pi) - (h)/(2pi) = (h)/(2pi)`

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when a hydrogen atom is raised from the ground state to an excited state

`P.E.` increases and `K.E.` decreases

`P.E.` decreases and `K.E.` increases

Both kinetic energy and potential eenrgy increase

Both `K.E.` and `P.E`. Decrease

When a hydrogen atom is raised from the ground state to an excited state

the P.E. decreases and K.E. increases

the P.E. increases and K.E. decreases

both P.E. and K.E. increases

both K.E. and P.E. decreases

The ionization energy of hydrogen atom is -13.6 eV. The energy required to excite the electron in a hydrogen atom from the ground state to the first excited state is (Avogadro's constant = 6.022xx10^23 )

`1.69xx10^(-20)` J

`1.69xx10^(-23)` J

`1.69xx10^(23)` J

`1.69xx10^(25)` J