In the hydrogen atom, if the reference l...

In the hydrogen atom, if the reference level of potential energy is assumed to be zero at the ground state level. Choose the incorrect statement.

The total energy of the shell increase with increase in the value of n

The total energy of the shell decrease with increase in the value of n

The difference in total energy of any two shells remains the same

The total energy at the ground state become `13.6eV`

Text Solution

Verified by Experts

The correct Answer is:

`U = - (27.2eV)/(n^(2)) + C , k = (13.6eV)/(n^(2))`
`E = - (13.6 eV)/(n^(2)) + C , DeltaE = 13.6eV((1)/(n^(2)) - (1)/(m^(2)))`
here in these question `C = +27.2 eV`

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If the potential energy is taken zero at ground state of hydrogen atom in place of infinity then

Total energy of atom will get changed

Binding energy of hydrogen atom in ground state will remain unchanged

Kinetic energy of electron in ground state will get changed

Energy of photon generated because of de-excitation of atom from first excited state will remain unchanged

The ionization energy of hydrogen atom in the ground state is

13.6 MeV

13.6 eV

13.6 Joule

Zero

Let the potential energy of the hydrogen atom in the ground state be zero . Then its energy in the excited state will be

`10.2 eV`

`13.6 eV`

`23.8 eV`

`27.2 eV`