Choose the correct statement (s) for hyd...

Choose the correct statement (s) for hydrogen and deuterium atoms (considering the motion of nucleus)

The radius of first Bohr orbit of deuterlum is less than that of hydrogen

The speed of electron in first Balmer line of deuterlum is more than than that of hydrogen

The wavelength of first Balmer line of deuterium is more than that of hydrogen

The angular momentum of electron in the first Bohr orbit of deuterium is more than that of hydrogen

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The correct Answer is:

We have `r prop (1)/(mu) , mu = "reduced mass"`
`(Kq^(2))/(r)= (mv_(e)^(2))/(r_(e)) = (mv_(N)^(2))/(r_(N)) , mv_(e)r_(e) = (nh)/(2pi)`

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Choose the correct statements(s):

In general more the ionisation energy more will be electronegativity.

Electronegativity increase means metallic character increases.

In general lower will be the ionisation energy, easier will be to remove electron.

Electron affinity of `S` is less than that of `CI`.

All the noble gases have completely filled `ns^(2)np^(6)` electronic configuration in their valance shell

First ionisation enthalpy of molecular oxygen (1170 kJ `mol^(-1)`) is almost identical with that of xenon (1175 kJ `mol^(-1)`)

Both `Xe^(+)PtF_(6)^(-)` and `O_(2)^(+)PtF_(6)^(-)`

None of the above

the speed along the orbit remains constant

the angular speed remains constant

the total angular momentum remains constant

the radius of the orbit remains constant